Quote:
Originally Posted by captainslug
The brightest LED Luxeon makes can output 540 lumens at 6.6W (provided you don't have to use a resistor). The resistor used to power the LED from a 12volt supply ends up consuming almost 2 watts.
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Could you not use two LED circuits to break the 12v down to 6 and 6?
I can't remember which type of circuit you'd use... I think you'd use two series circuits in parallel.
+[-|-|-|-|-|-]-
+[-|-|-|-|-|-]-
+ = input
- = output
[-|... = LED's in series
Something like that.. but it's probably wrong.
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"¿ʞɐǝɹɟ ɐ ǝɹ,noʎ uǝɥʍ 'ʇı ʇ,usı 'ʎlǝuol s,ʇı"
Quote:
Originally Posted by tasdrouille
Because bean counters always win, that's why.
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