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Old 10-12-2011, 02:39 PM   #21 (permalink)
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I can run my Sanyo (via two SSRs) at 4 amps 24-7 and the heat sink doesn't get
any warmer than 72 degs F.. (With the air temp between 65 & 70 F).

Maybe that's the 5 watts of wasted power..

That big heat sink was a waste of metal... I could have bolted the SSRs onto plastic..

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Old 10-12-2011, 10:48 PM   #22 (permalink)
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For shure , disipating 4w is easy

Just Think about your desktop CPU dissipating hundred of watts with a much smaller heat-sink

The only question in electronic design is how much raise in temperature you can allow for your component to survive. In your example, the casing of the SSR itself may be enough to dissipate the heat to a usable temperature
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Old 10-12-2011, 11:02 PM   #23 (permalink)
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This is the result of my simulations of this circuit

I've build it whit closest equivalent pieces available in my simulation software (yes yes I should get the new version , i'm just to lasy to crack the new one )

I've play allot whit components, and tried to tuned it as much as I could

2 possible results
-Circuit does nothing
-Circuit blow out fuses while shorting the grid

Case closed
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Old 10-12-2011, 11:15 PM   #24 (permalink)
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What's with the 10 ohm resistor in the upper left? Seems like it's nothing but a 1440 watt load on the grid..
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Old 05-05-2012, 09:33 AM   #25 (permalink)
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Quote:
Originally Posted by Xringer View Post
What's with the 10 ohm resistor in the upper left? Seems like it's nothing but a 1440 watt load on the grid..
Yes it is a load on the grid. Since My ac source is ideal , I need a way to monitor if any current goes back to the grid

Sorry for the delay
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Old 05-05-2012, 10:03 AM   #26 (permalink)
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LOL! I had forgotten what this thread was about.
When I looked up at the circuit diagram, I was thinking, 'what kind of battery charger is this?'..

Then I went back and saw the Youtube vid.. Something that is was
(until this morning) very dim in my memory.

That's what happens when you get old. You run down to the basement
and once there, you have no clue as to why you are there...
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Old 05-05-2012, 12:02 PM   #27 (permalink)
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In the very first post in this thread, the very first thing i noticed was the capacitor in series with the battery!

That device is simply an expression of wishful thinking!
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Old 05-05-2012, 01:18 PM   #28 (permalink)
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Quote:
Originally Posted by jakobnev View Post
In the very first post in this thread, the very first thing i noticed was the capacitor in series with the battery!

That device is simply an expression of wishful thinking!

That was my opinion too. But, it did make me wonder.
If a car battery would be quickly discharged(as claimed),
and if the semiconductors didn't dissipate but a small percentage of the watt hours stored in the battery,

Where did those watt hours go??
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Old 05-05-2012, 04:13 PM   #29 (permalink)
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For a 10uF capacitor to pass the charge of a reasonably sized car battery (60Ah) through it, it has to end up with 21.6 billion volts over it. (21600 Coulombs into 0.00001 Farads)

Now most capacitors will break down somewhere () before 22GV, so even if the assumptions were true (they just aren't tho) it would at best be an apparatus for destroying capacitors.
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Old 05-05-2012, 08:25 PM   #30 (permalink)
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Yeah, I think the cap would have to be a much larger size to pass much current.
Even if the full-wave made it look like 120hz, that's still around 132 ohms of series resistance
(Capacitive reactance XC). Might pass 0.1 amp..

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