Quote:
Okay, there are some good ideas here. So, what if we follow Jamesqf's idea, combined with dcb's response? Let's have a gasser and an identical EV drive a distance so that the gasser uses one gallon of gas. The EV will use only 3/7 as much energy, or
(34 kWh for a gallon) x 3/7 = 14.57 kWh
So, Jamesqf, there's your conversion factor--
1 gallon of gasoline = 14.57 kWh
Nope, the electric boys wouldn't accept that.
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I can't put my finger on it - probably because I've only spent the time it took to read the post thinking about it...
That suggests that a higher efficiency EV in the experiment, what should be an independent variable, results in less energy in a gallon of fuel. This makes my intuition gland tingle.... It not sitting well with me (just yet) from a conservation of energy stand point.