Quote:
Originally Posted by Jim Bullis
What happened to the Ernie Rogers that argued for a 40% adjustment for the efficiency of the power plant that made the electricity?
|
Aw, jeez, I'm asleep at the wheel here. For every KJ of power that makes it to the grid, it takes an average of 2.5KJ of fuel.
Cost equivalence: 18.5KWh = 1 gal gasoline for me today. Wildly variable, changes daily, different everywhere.
Well to Wheels greenhouse gas equivalence: 15.2KWh = 1 gal gasoline
Energy equivalence of pure electricity: 34 KWh = 1 gal gasoline
Energy equivalence for grid average (guesstimated at 40% efficiency) plus 7.2% transmission losses: 12.6KWh = 1 gal.
I'm guesstimating 40% thermodynamic efficiency average, since most fossil-fueled plants get 36-40%, nuclear is slightly lower, and non-combustion methods could be said to be ~100% thermodynamically efficient for our purposes.