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Old 12-24-2011, 02:29 AM   #24 (permalink)
thingstodo
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Stuff done during the summer - How much force is needed to move an S10?

The sketch shows the rear hub, the horizontal 2 x 6, the vertical 2 x 4, the scale, and the video camera.

The measurement on the scale reads about 180 lbs. This is at 15 inches from the center of the wheel hub, the radius of the rear wheel. So this is the force exerted on the ground to move the truck forward at idle speed.

Press the accelerator gently, check the force on the scale

I saw the weight go momentarily up to 240 (maximum for the scale)
- then the back of the truck lifted off the ground
- then the 2 x 6 on the passenger's side broke and the passenger's side rear wheel started to accelerate

Check the available internet information. From EV Calculator with a 1994 chev s10 extended cab, an ADC FB-4001A motor, Concord 12105 batteries, a Curtis 1231C controller, 96V battery pack, 205/75r14 tires, 0 incline, 0 headwind, default rolling resistance and brake/steer resistance, the torque required to run the truck at 10 mph (the lowest calculated speed) is 41 foot-lbs at the motor. Put through a 3.43 rear end, 41 * 3.43 is 141 foot-lbs. With a 15 inch radius, that gives 141 foot-lbs * 12 inches/1 foot / 15 inches = 112 lbs of force. This is relatively close to the 180 lbs of force measured by my crudely constructed system.

The left sketch is an overhead view looking down on the rear end. The right is a side view from the driver's side of the truck
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Last edited by thingstodo; 12-24-2011 at 12:34 PM.. Reason: The attached picture was missing - it was too big
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