Quote:
Originally Posted by redyaris
As far as i know you can use pounds of air and ponds of fuel to do the calculations so you will have to convert volume of air to weight and volume of fuel to weight. at which point you can do the calculation to find mile per gallon.
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Oh so... Let's see... Is this correct?:
1 litre of air weighs about 1.29 grams.
So;
1 L = 1000 cc
2000 RPM = 1000 RPM of combustions
1.29 (grams) / 15.5 = .08322 grams of fuel (I am using 1.29 g as that is a litre of air, and the maximum displacement at 100% VE of the engine is 1 L; so it works out.)
Fuel Consumption = 0.08322 * 0.20 (throttle) * 0.80 (VE) * 1000 (RPM of combustions)
= 0.01664 * 0.80 * 1000
= 0.01331 * 1000
= 13.31 grams of fuel burned per minute
1 litre of gasoline weighs ~737.22 grams
So, 13.31 / 737.22 = 0.018; or 1.8 %
1.8 % of a litre is 18cc
So 18 cc of fuel is burned in this situation?
Am I correct?
