Quote:
Originally Posted by elemein
Oh so... Let's see... Is this correct?:
1 litre of air weighs about 1.29 grams.
So;
1 L = 1000 cc
2000 RPM = 1000 RPM of combustions
1.29 (grams) / 15.5 = .08322 grams of fuel (I am using 1.29 g as that is a litre of air, and the maximum displacement at 100% VE of the engine is 1 L; so it works out.)
Fuel Consumption = 0.08322 * 0.20 (throttle) * 0.80 (VE) * 1000 (RPM of combustions)
= 0.01664 * 0.80 * 1000
= 0.01331 * 1000
= 13.31 grams of fuel burned per minute
1 litre of gasoline weighs ~737.22 grams
So, 13.31 / 737.22 = 0.018; or 1.8 %
1.8 % of a litre is 18cc
So 18 cc of fuel is burned in this situation?
Am I correct?  |
0.20 ( throatle ) is a problem because it does not tell you the mass of air getting into the engine. The volume will always be 1000cc regardless of throatle position, what changes is the mass/density of air in the cylinder when the valve closed.
The 0.8 volumetric efficiancy is at optimum engine speed, probably at max torque at wide open throatle.