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if we assume contact patch is governed approximately by air pressure.
and we use some random numbers.
due to x load and y pressure, and z circumference. same in both cases.
a 10" wide tire deforms 2" of the tire circumference giving 20 sq inch of contact patch
a 4" tire will have to deform 5" of circumference to support the same load at same pressure.
i argue that 5" is greater than 2" of the circumference of the tire that has to deform to conform to the flat road. for tires of equal diameter
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