[MPaulHolmes]

Same length, but different current. It basically turns each Igbt into A mosfet. Higher current? Fine! But you will have a higher voltage drop, which causes it to use less curtent. Heres the math:

V1 + i1*R = V2 + i2*R. The point above both igbts to the point where both M+ connect is the same drop in voltage. R is the same for both because we are using equal lengths of wire.

So,

V1 - V2 = i2*R - i1* R
V1-V2 = R*(i2-i1)
i2-i1= (V1-V2)/R

So, the difference in current between the 2 IGBTs is smaller the bigger R is. And, its small when V1-V2 is small. But we cant control V1-V2.

In our case R is about 0.00005 Ohms. So,
i2 - i1 = 2000*(v1-v2).
So, if they differ by, say, 0.01v in their drop, the igbts will be within 20 amps of each other. Without the resistance, that 0.01v difference could be catastrophic.