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Old 04-23-2014, 05:19 AM   #6484 (permalink)
flores
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haaaaaaaaaaa.. I get it..

because: V = R * I and R is fixed and I varies V will also vary, and you calculated that 3 feet of 2 gauge wire is enough R to vary V enough at max I, right?

To make the picture complete.. where does this voltage drop occurs? Between the collector and the emitter of the IGBT?
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