Quote:
Originally Posted by P-hack
Your boost explanation so far makes sense, except here, I see the voltage alternates on the inductor, but the current is fairly stable. There's some current ripple, but the whole point of the inductor is to maintain current, no? If you are drawing 400 amps at whatever power level from the battery, the boost inductor needs to be able to handle ~400 amps it seems (the two are in lock step current wise in ltspice, I think that is kinda how series current works).
Edit: would be nice if I was wrong.
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Most of the losses on an inductor are associated with the ripple. So the smaller the ripple, the less I2R and core losses. It might be worth to make a simulation with larger values of inductance and see how the current and efficiency change.
Regarding the current: Say a 12V light bulb feed with PWM with a 50% duty cycle, and an input voltage of 24V.
Will the bulb burn? Depends.
If the switching frequency is 1Hz, it will surely burn!
If the switching is fast enough the filament temperature will average due to thermal inertia. This is also true for magnetic fields and the wiring on the inductor.
Same with AC current. RMS reading is 13Amps, but peak current is 18A.