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Old 07-19-2015, 12:20 AM   #5 (permalink)
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ChargE (not yet running) - '92 Mazda MX6 LX
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Originally Posted by oldtamiyaphile View Post
The EM calculator tells me that equates to 710Wh/km.
Jack Rickard is getting 750 - 1100 w-h per mile in a 7777 lb cadillac escallade running DC motors and an automatic transmission. In my opinion, your van should do quite a bit better than 710.

Based on 3800 lbs a decent conversion should get you 380 w-h per mile. A bad conversion maybe 450 w-h per mile. A Great conversion 350 w-h per mile. Do you run cargo or towing a lot? If not, I would not put the extra weight into your nominal calculations.

With low-speed driving and hyper-miling, running an AC system and using regen to stop at lights (when coasting in traffic just won't cut it) I'll bet you could beat 350 w-h per mile.

I want to travel 100km on a charge so I need a 71kWh pack. This is at odds with the EV source calculator which predicts a nearly 60 mile range on a 28.8kWh pack. They don't factor in that I drive all low speed streets and would be hypermiling, I expect I would see a healthy 80miles on such a pack.
100 miles with a margin for error, and using some heat, and maybe power steering and brakes ... 400 w-h per mile ... 10% margin for error or if you want to charge to 95% and discharge to 10% (in an emergency case) .. 45 kw-h would be my guess.

My van has a good amount of space under the floor so all the batteries would be mounted below my CG, improving ride and handling (maybe!).
If you have the room, centering the mass of the batteries at the centerline of the wheels is supposed to affect the handling of the vehicle the least. This is what I read of Teslas and such. I have no experience with having lots of room for batteries

How would I more accurately predict my required capacity based on my current diesel usage?
That's an excellent question that I've never read before. There are a few things you use fuel for when stopped that electrics don't, like idling .. but there are things you get for free, like heat, that electric uses energy for. I would think there are too many variables to get a decent converted number.
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