Quote:
Originally Posted by e*clipse
But you don't get something for nothing, and the current will have to be increased if the voltage is decreased. This extra current will result in more I^2R heating, demanding more heat rejection just to keep the same continuous power output.
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Just to clarify, the motor windings will see the same current, if you have 100 amps going through two fields in series, or 200 amps split between two 100 amp fields in parallel, sameo-sameo as far as the motor is concerned. The supply will see higher currents, but not really within the motor itself, since you were focused on the motor heat issue. Same is true for proper rewinding for lower or higher voltage, in that the power stays the same.