I tried to do some napkin math, but realized I'm technically missing some details. Does that regen of 15-20A have 12v or pack voltage? I'd assume it would be pack voltage, which I don't know. Google says 144V.
20A*144V = 2,880W of power re-generated.
Gallon of gas = 33.7 kW's of power. 33.7 x .4 (efficiency of ICE) = 13,480
So the amount regenerated converted to a gasoline equivalent would be .21 gal
If it is based on the 12v system you can just reduce by a factor of ten and be close. So ~.02 gallons equivalent recovered. So as long as you use less than .02 gallons then I think option 2 would be more efficient.
Does my thought process make sense? That's pretty much how I would consider the problem, so if anyone could double check the math and thought process I'd appreciate it.
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