Quote:
Originally Posted by trebuchet03
Combustion is a chemical process - the nominal outputs are predictable based on the empirical science that is chemistry. Combustion is, in a crude sense, a change in chemical bonds -- nuclei are (at least proton count of the constituent atoms) are left alone.
When you change the proton count (going from hydrogen to helium) - that's an atomic process. You're changing atoms, not chemicals. You can disagree if you want, but you're not disagreeing with anyone in particular - you're disagreeing with the ambiguous entity that is chemistry.
Additionally "What if the hydrogen always..." is not an argument - this isn't a "what if" situation. This is a reaction, a well documented, observed and explainable reaction.
2H2 + O2 → 2H2O(g) + heat
Nice an balanced.... All atoms are accounted for on each side...
Chemical Equation - please read about balancing reactions. Then, please provide the chemical equation for how hydrogen and oxygen turn into helium. This isn't an unreasonable request if you're going to make that claim.
Now if you're just joshing us  Have a beer on me for a well played and humorous post  |
Actually, that's a VERY unreasonable request since nowhere in this thread or any other thread did I ever say that. Hydrogen and oxygen are ALWAYS going to recombine into water... ALWAYS, which is PROOF of an inefficient burn if water vapor is a product. Reading posts is tricky sometimes. We mostly just want to see what we want to see and don't absorb the true content of what we read.
Here's an equation for you though:
H2 + FIRE (will never, ever, not in a million years) = H2.
That's FREE ENERGY and doesn't exist SO, if we say H2 + O + fire = H2O(water)... well, it's obviously BUNK and that's what some are saying.
Once again, I am stating *clearly*, whether the by product is helium or not, an efficient burn of H2, WILL NEVER PRODUCE H2 and since that's 2/3rds of the contents of water, you wont get water either.
Anyway, this should be common sense but it's doesn't seem to click with some. I'm officially outta here. ("here"= this thread), another neat equation.