Quote:
Originally Posted by Joggernot
Just did the calcs for my CRV 1.5L turbo. At 2000 rpm I get 1173 ft/min piston speed (2 x 3.52 x 2000 x 60/720 = 1173). The original formula was for ft/sec so multiply by 60 sec/min to get final result. This seems to show that 2000 rpm for my engine is "ideal".
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Check my numbers please:
Stroke = 3.52"
TDC to BDC to TDC ( or vice versa/revolution )= 2X 3.52"/ rev= 7.04"/rev
7.04" X 2,000 rpm = 14,080"/minute
14,080" / 12"/foot = 1173.33 feet/minute
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If you're looking for feet/second, and there's 60-seconds/minute, wouldn't we divide by 60?
1173.33/60= 19.55 ft/sec?
I couldn't find the material attributed to 'Taylor'.