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dcb · 01-27-2009, 08:37 AM

I don't know if there is a 100% fix either. I don't know what happens to the hold voltage when the alternator goes out. I am assume it is a function of supply voltage, but it is conceivable that they got fancy with the hold voltage drivers, in which case supply voltage could drop below the hold voltage.

resistor experiments:
r2>=2520 ohms (base current @peak =.005a @hold (11 volts) = .00063a)

A 50k seems to work too for r2, so I don't think it is too critical. And a 50k offers much more protection than 2520 so I might just go with that. it means about 0.0000036 amps through the base in "hold" which is about 72 times the base cutoff current, and .0003 amps at peak.

rx=50k ohms

01-27-2009, 08:37 AM	#26 (permalink)
dcb needs more cowbell Join Date: Feb 2008 Location: ÿ Posts: 5,038 pimp mobile - '81 suzuki gs 250 t 90 day: 96.29 mpg (US) schnitzel - '01 Volkswagen Golf TDI 90 day: 53.56 mpg (US) Thanks: 158 Thanked 269 Times in 212 Posts	I don't know if there is a 100% fix either. I don't know what happens to the hold voltage when the alternator goes out. I am assume it is a function of supply voltage, but it is conceivable that they got fancy with the hold voltage drivers, in which case supply voltage could drop below the hold voltage. resistor experiments: r2>=2520 ohms (base current @peak =.005a @hold (11 volts) = .00063a) A 50k seems to work too for r2, so I don't think it is too critical. And a 50k offers much more protection than 2520 so I might just go with that. it means about 0.0000036 amps through the base in "hold" which is about 72 times the base cutoff current, and .0003 amps at peak. rx=50k ohms __________________ WINDMILLS DO NOT WORK THAT WAY!!! Last edited by dcb; 01-27-2009 at 12:33 PM..