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Reducing electrical loads
How much do you guys figure dropping a 60W load from the alternator would save?
I'm considering dropping my DRL on the Burgman. |
60 watts is about .08 hp. Even assuming the alternator is only 50% efficiency, you'd be looking at a savings of .16 hp. I think the fuel economy increase would be at the limit of your ability to detect. However, it would make a difference, and everything helps?
-Steve |
You can save another 40-150 watts by changing all the running / signal / brake lights to LEDs (depending on the car/number of bulbs),
at least at night. If you do both changes at the same time, it might make a difference you can notice. |
The 'burg has a built in alternator, right?
It probably only produces about 10-20 amps, max. For posterity, the one on my tractor's engine is built in (it's part of the flywheel). It takes about .6 HP to make 15 amps @ 12VDC. (According to Briggs, IIRC) 15*12 = 180 watts Assuming 50% efficiency, 180 watts takes about .5 HP to make, the rest of the power loss is heat, I presume. If your 'Burg makes 50 HP max (unlikely, probably closer to 30), you're looking at 1-2% of your total output being used for max load on the alternator. Relatively insignificant, but you may get something from it. |
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And I don't have any money for anything else at the moment, unfortunately. |
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http://www.superbrightleds.com/store...157-w30-ra.jpg Product Listing - CAR Or a multi directional one like any of these: 1157 1156 Superlumination.com leds (Automotive Replacement Light Bulbs, Headlights, Foglights & Lamps) I didn't realize at first it was for a motorcycle; so it would save all the time, not just at night. I use them in my bike, very happy with them. They are kind of expensive though. |
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