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mora · 10-30-2010, 06:42 PM

Good info.

So I suppose maths go like this:

P=power, U=voltage, I=current, R=resistance

P=U*I -> I=P/U -> 1500W / 220V = 6,82A
R=U/I -> R = 220V / 6,82A = 32,26 Ohm (max. resistance I assume, for that voltage)

then, if we use 96V instead of 220V
I=U/R -> 96V / 32,26 Ohm = 2,98A
P=U*I -> 96V * 2,98A = 286W

Oh. For 220V element and 110V operating voltage power would be 375W, 1/4 of full power.

But then. 1500W 110V element with 96V:

R -> ~8 Ohm
P -> 1150W

Much better. One element produces more power than two 220V put in paraller. Two units provide twice power if put paraller.

10-30-2010, 06:42 PM	#11 (permalink)
mora EcoModding Apprentice Join Date: Oct 2009 Location: Jyvaskyla, Finland Posts: 143 Golfwagen - '89 Volkswagen Golf mk2 90 day: 107.14 mpg (US) Thanks: 47 Thanked 35 Times in 28 Posts	Good info. So I suppose maths go like this: P=power, U=voltage, I=current, R=resistance P=UI -> I=P/U -> 1500W / 220V = 6,82A R=U/I -> R = 220V / 6,82A = 32,26 Ohm (max. resistance I assume, for that voltage) then, if we use 96V instead of 220V I=U/R -> 96V / 32,26 Ohm = 2,98A P=UI -> 96V * 2,98A = 286W Oh. For 220V element and 110V operating voltage power would be 375W, 1/4 of full power. But then. 1500W 110V element with 96V: R -> ~8 Ohm P -> 1150W Much better. One element produces more power than two 220V put in paraller. Two units provide twice power if put paraller.