Quote:
Quote:
Originally Posted by Xringer View Post
So, if I had a 10,000 farad capacitor charged up to 9 Volts and I connected a 9 ohm resistor across it, I wouldn't get 1 Amp of current flow when I flipped the switch?
No. If you look at instantaneous current flow, it will follow the same exponential decay curve as that voltage plot. You'd have a current flow of many amps for the first fraction of a second, declining to a fraction of an amp after several seconds. A battery would supply nearly constant current/voltage until it's depleted.
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jamesqf,
I believe you may be mistaken.
From V=I*R we get I=V/R. Putting in 9 for the volts (V) and 9 for the ohms (R) we get 1 amp (I). Now as the current flows, the voltage in the capacitor drops, so the current gets lower with time, perhaps along the lines of a time constant RC. But the maximum current at the start when the switch is first closed is 1 amp.