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Old 09-26-2013, 04:48 PM   #1096 (permalink)
TheEnemy
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I just found a couple of mistakes, I'll post the base equations and how I came about what I got.

Temperature radiated = 0.9*0.000,000,056,704*T^4
where 0.9 is the accepted radiated percent of earth at our temperature range.
0.000,000,056,704 is a constant
T is the temperature on the Kelvin scale.

Examples at 0C/274.15K average earth radiates 288.276 w/m^2
at 12.12C/286.27K = 342.74 w/m^2
at 16.12C/290.27K = 362.297 w/m^2
at 40C/314.15K/104F = 497.055 w/m^2

Energy absorbed by earth is approx. 0.7*TSI/4
Where 0.7 is the percentage of energy absorbed by earth (varies significantly by region and temperature)
TSI is the Total Solar Irradiance (currently over 1361w/m^2)
The /4 is due to converting from the surface area of a circle (what the sun sees) to the surface area of a sphere.