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4000watt = batteryPackVoltage * sqrt(3/2) * 8.3 * 0.88
So, batteryPackVoltage = 447 volts in that case would make 4kW real output power of the motor, assuming that the motor was 100% efficient. But let's plug in their value of battery pack, and maybe that will give us an idea of motor efficiency too:
4000watt = 380 * sqrt(2) * sqrt(3/2) * 8.3 * 0.88 * efficiency.
4000watt = 380 * sqrt(3) * 8.3 * 0.88 * efficiency. HEY!!! After all that stuff I went through, we finally get to your formula:
P = sqrt(3) * V * I * cos (fi), with an efficiency of
efficiency = 83%
haha
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