[gumby79]

Originally Posted by teoman

I
.... i can control the flow more precisely and i have some ideas on using compressed air instead of a pump (mainly because i am a diver and I have lots of compressed air tanks).
...
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Dive /scuba tank air pressurizing the resavor. IS how i read this. Air over water. Am I following correct?

Problem I was trying to identify
At 100 psia* =pure water boils at 328°f
At 150psia * =359°f
*a=absolute not including the 14.69psi of ambant or altitude compensation.
Your boiler will have to ofer come this pressure


The waterhamer arrester would smooth the pulse of the multi diagram pumps like the Shurflo RV pump. Allowing for a more consistent injection volume. A presure regulator would do a better job,imho.

from the article
design, quite logically, on the required delivery of water or water-alcohol mixtures to our target. Take a simple hypothetical situation of 300 horsepower which, at a B.S.F.C. of .5 lb per horsepower per hour (150 lbs of fuel)...which equates to about 22.62 gallons of gasoline per hour (150lbs / 6.63 lbs per gallon = 22.62). If we are trying for 15% of the mass using 100% water the 15% is .15 x 150 = 22.5 lbs of water per hour.

22.5 lbs water / 8.33 lb per gallon = 2.7 gallons per hour water consumption. To calculate cc's we multiply 2.7 x 3785cc per gallon = 10,219 cc's. To calculate the cc's/minute of water needed we to divide by 60 which gives us 170cc's per minute.

We used the same planning when we were using actual fuel injectors to deliver water at Bonneville.

300hp only needs 170cc/min a very small volume
Using the 1.2 TDI VW Polo 2013 60hp and an assumed .5lb/hp hour
Water required/hr by mass=(.5×60)/6.63=4.52lbs/hr
15% of fule =4.52×15%=.68lbs water /hr
Convert to ga/hr.68÷8.33=.081ga/hr
Ga to cc/hr=308.4cc/hr
Cc/hr to cc/min 308.4÷60=5.14cc/min
15%h2o to fule at full power (60hp) =5.14cc/min
Now take the 5.14cc/min and calibrate your injectors .
Driving at hp peek ,1L would last194.55min