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Old 01-29-2011, 09:36 PM   #1 (permalink)
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Is my math correct?

If your car at idle uses .25gph and you engine on coast for a mile downhill at a constant 60 mph, you have then used only .00416 gallons of fuel. That equates to doing this 240 times 'engine off' to save a gallon, or eternal vigilance!


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Old 01-29-2011, 11:10 PM   #2 (permalink)
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60MPH/.25GPH = 240 MPG engine-on coasting @ 60 MPH.
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Old 02-01-2011, 10:17 PM   #3 (permalink)
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Quote:
Originally Posted by BHarvey View Post
If your car at idle uses .25gph and you engine on coast for a mile downhill at a constant 60 mph, you have then used only .00416 gallons of fuel. That equates to doing this 240 times 'engine off' to save a gallon, or eternal vigilance!
If you can maintain the 60 MPH coast speed while in gear using DFCO then 0.00 gallons consumed, same as engine off coasting.
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Old 02-01-2011, 11:32 PM   #4 (permalink)
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my car uses much more than that unless it's warmed up. my big EOC gains are when the car's not warmed up yet. Much less penalty for idling when warm.
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Old 02-01-2011, 11:38 PM   #5 (permalink)
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If you can maintain the 60 MPH coast speed while in gear using DFCO then 0.00 gallons consumed, same as engine off coasting.
That would be a steep hill!
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Old 02-02-2011, 02:36 PM   #6 (permalink)
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It's better to think of it in a real world drive. If you do a 10 mile drive averaging 40 mpg for 9 of those 10 miles, and incorporate that 1 mile downhill, it looks like this:

EOC
9 miles @ 40 mpg.
.025 gal/mile times 9 = .225 gal consumed for 9 miles
.225 gallons consumed for 10 miles = 44.44 mpg
NICE-on
9 miles @ 40 mpg.
.025 gal/mile times 9 = .225 gal consumed for 9 miles
.25 GPH consumed for 1/60 of an hour = .25/60 = .004167 gal.
.229167 gallons consumed for 10 miles = 43.64 mpg

At a more realistic 30 mph, the NICE-on idle usage doubles because the glide takes twice as long, and the car uses .23333 gallons for 10 miles = 42.86

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