Quote:
Originally Posted by fit7ad
High school physics teaches us that P = V * I. This is true even if you drop the voltage across a diode instead of a resistor. You will need huge heat sinks to dissipate that kind of power.
A better way is to use a PWM circuit with a power MOSFET. You can look for DIY kits/circuits or DC motor speed controllers. You might still want a bypass switch for 100% brightness since the controller is not 100% efficient and it probably won't give you 100% duty.
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I just knew I shoulda went to high school!
I've used small diodes for years to drop voltages, but never really ran any at high currents. Down at a few MA, they down seem to make much heat at all.
Anyways, it's not that much per diode. 5A x 0.7V = 3.5 Watts each.
Depending on the size of the diode, you might not even need a heat sink..
I remember about 35 years ago making a 12V 30A supply for a ham radio project. I mounted the 4 diodes on a big heat sink that was bolted to the chassis. So, I never noticed it getting hot. But, one cold winters day,
I was out in a cold radio hut and noticed how warm it was by my old 12V PS.
Running about 20A, it must have been putting out a lot of heat from the whole chassis..
Anyways, I was wrong about the lamp current too.
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Since adding the diode drops in series with the lamps will increase the overall circuit resistance and therefore drop the current (saving some battery/Alt power)..
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At the cost of less candle power..