re-setting the blower motor

[mort]

Originally Posted by SentraSE-R

It's all there in Mort's post #7. The power consumed (wattage) remains the same, but the amperage through the fan motor drops to half if the resistance in the circuit doubles by your adding resistors.

No it doesn't. Look again. The motor alone uses 100 watts. The motor with 12 ohm resistor uses a total of 14 watts, 12 through the restor and 2 through the motor. It isn't the most efficient way to slow things down, but it does reduce the total power substantially.

-mort

[mwebb]

E = I x R
voltage = current in amps x resistance in Ohms

12volts = 12volts no matter what

so if R is increased then I must decrease ...
if resistance increases , current flow must decrease if voltage is constant

you can not break OHMs law , no matter how hard you try .

but
it will not change your FE more than the noise in your FE calculations

[Andrew63]

Originally Posted by mwebb

E = I x R
voltage = current in amps x resistance in Ohms

12volts = 12volts no matter what

so if R is increased then I must decrease ...
if resistance increases , current flow must decrease if voltage is constant

you can not break OHMs law , no matter how hard you try .

but
it will not change your FE more than the noise in your FE calculations

Ohm's law also says

Power consumed = Voltage * Current, and Current = Voltage / Resistance, so it can be restated as

Power consumed = [Voltage]^2 / Resistance

As resistance increases, the power consumed decreases for a constant voltage.