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Originally Posted by IamIan
It isn't a fixed number.
It varies with context... temperature alone is insufficient data to determine the final expansion ratio.
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If you're talking about saturated steam, then yes, it does.
Look, the example isn't perfect, and very many simplifying assumptions were made in an attempt to make it understandable. Some of these assumptions tried to give as much of an advantage to the idea of magically making steam do useful work out of exhaust heat, as was possible.
Are there flaws with the example? Sure there are! It's necessary to perform integration to more accurately reflect what would happen with this example, which is beyond the capabilities of the casual reader. Could I do the integration? Sure, but to what point? It'd just show the same thing in the end, that water injection into spent combustion gases is a dead-end idea. It'd satisfy you, perhaps, but it'd make others only more confused.
Could an example model be rigged up such that it uses integration to arrive at a more accurate final state? Sure, but I'm not going to do it. Maybe the guy with the Bachelor of Science in Mathematics could give it a whirl.
In the end, the example tries to mix together an ideal process using the ideal gas law, with real-world properties of water. Something's gotta give.
Quote:
Originally Posted by IamIan
I'm saying if you agree with either the ideal gas law or the principles it is based on ... than by confining the expansion of the steam in a limited volume container , as we have in this example ... than it follows from the ideal gas law and it's principles that the partial pressure of the steam must be higher than it would be if it's expansion were not restrained by the limited volume of the container ... to claim otherwise violates the ideal gas law and the principles it is based on.
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And you're missing the point here. In the real world, there wouldn't be superheated steam in the same vessel as liquid water, at least not at the given example. It leads back to that whole idea of mixing a theory based on ideal properties of a gas, with real-world data about steam.
Quote:
Originally Posted by IamIan
And as you already wrote previously ... we did compression work on the system from the outside when we added the liquid water.
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And I also said the amount of work performed in compressing the gas by the addition of the water was so small as to be negligible. After all, you're talking about a compression of 1.025:1.
Quote:
Originally Posted by IamIan
The steam we have is the result of the energy that will be transferred from the initial gasses to the liquid water we put in ... Who's adding more than that?
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You're trying to, by going by the 1700:1 thumbrule, which has already been shown to be incorrect.
Quote:
Originally Posted by IamIan
In this part you quote from me ... I'm claiming the amount of partial pressure from phase changing a given amount of liquid water to steam will be effected by how the limits of the volume it can expand into ... which is what the ideal gas law requires.
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And you're neglecting the real-world properties of the water.
Quote:
Originally Posted by IamIan
0.96g of liquid water + 0.04 grams of steam confined to a 600cc container will not have the same pressure if the same 0.96grams of liquid water + 0.04 grams of steam is confined to a 100cc container ... the pressure will also be different if the same 0.96grams of liquid water + 0.04 grams of stream is confined to a 10cc container.
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You are correct, but not for the reason you think.
Did you consider that in each of your 600 cc and 100 cc and 10 cc cases, the water and steam will adjust to fit the volume dictated by the temperature of the system? In the 100 cc and 600 cc cases, the liquid will boil off to admit more steam into the vapor part of the system. The boiling off will absorb heat from the liquid water, causing the liquid to cool. The steam will also cool so as to maintain equilibrium temperature with the water. This will cool off the system as it goes to equilibrium, which will be at a lower final temperature. This follows the properties of saturated steam. The ideal gas law does not apply here.
Similarly, the steam, now at a much higher pressure in a 10 cc vessel than in the original 40 cc vessel, will condense out into the liquid. This releases latent energy of vaporization into the system, causing the temperature of the system to rise until the system again goes into equilibrium. Again, this reflects the properties of saturated steam, not the ideal gas law.
Quote:
Originally Posted by IamIan
Although the ideal gas law shows this and requires this ... the mechanism for why this happens is easier to see in the kinetic theory of gasses ... although I don't see a need to go that far into the principles the ideal gas law is based on ... I think the ideal gas law should be adequate on it's own.
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Sure, for an initial condition gas that we're treating as an ideal gas for purposes of an example.
Quote:
Originally Posted by IamIan
And honestly ... I don't understand why you seem to be arguing against the ideal gas law here???
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Because, like I just said, water and saturated steam do not follow the ideal gas law. There are saturated steam tables for this.